Timeline for SDR: How are I and Q determined from the incoming signal in quadrature sampling on the receiver side?
Current License: CC BY-SA 4.0
5 events
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Dec 17, 2020 at 15:56 | vote | accept | Steven | ||
Dec 17, 2020 at 13:28 | comment | added | Phil Frost - W8II | @Steven Does ham.stackexchange.com/q/10454/218 answer your question? If not, please do ask another. | |
Dec 17, 2020 at 10:05 | comment | added | Steven | Thank you very much. So in principle one could just shift down the signal so that the frequency of interest is near 0Hz, then report the instantaneous amplitude at about twice the bandwidth per second. Is this is correct, why is this not done? Is it just that one easily gets $I$ and $Q$ as a byproduct of this downshifting process using the quadrature mixer, and so it would actually be extra work to re-convert $I$ and $Q$ to a single sample? Wouldn't this extra step halve the bandwidth needed to report samples between the receiver and software? | |
Dec 16, 2020 at 22:57 | history | edited | Phil Frost - W8II | CC BY-SA 4.0 |
added 275 characters in body
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Dec 16, 2020 at 22:38 | history | answered | Phil Frost - W8II | CC BY-SA 4.0 |