Timeline for Solid angle for different E/H plane beamwidths
Current License: CC BY-SA 4.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jan 23, 2020 at 18:44 | answer | added | Phil Frost - W8II | timeline score: 1 | |
| Jan 21, 2020 at 6:58 | history | edited | pymekrolimus | CC BY-SA 4.0 |
An ellipsoid is not coincident with a sphere.
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| Jan 21, 2020 at 6:52 | comment | added | pymekrolimus | You're right - an ellipsoid is not coincident with the sphere. I will remove that part. Instead the solid angle on the elliptical beam should be some fraction of the surface area of a hemisphere. How would I go about integrating this? | |
| Jan 21, 2020 at 6:33 | comment | added | tomnexus | I think things are made worse by the addition of the sphere analogy. If you must project the beam onto a unit sphere, you'll find the area is the same as the solid angle. But there's no need to invoke a sphere to find solid angles. In your first case - there is no hemisphere, just a portion of the unit sphere. In the second case, there's definitely no ellipsoid; an ellipsoid isn't coimcident with a sphere at all (except in the trivial case). How about "just" integrating to find the solid angle of the elliptical beam itself, with your first formula? | |
| Jan 21, 2020 at 4:54 | history | asked | pymekrolimus | CC BY-SA 4.0 |