20

Dispelling the Myth To begin with, the typical HF SWR meter does not have the ability to separately sample the forward and reverse power, voltage, or current. Any description of the device or its circuitry that suggests this capability is flawed. We can show this empirically with two different experiments. Experiment 1 Connect a 100 ohm resistor directly ...


12

Remember that carriers are selling bandwidth, that’s it. Actually, they are overselling it, exactly like cable modems (but that's another story). If everyone in the coverage area of a cell tower tried to make a call at once, most of them would be unhappy. The carriers paid a boat load of money for their chunk of spectrum and their overriding goal is to ...


10

What is dBm? dBm stands for decibels relative to one milliwatt. Decibels represent multiplicative factors, or ratios; by establishing a specific reference level they can instead be used as absolute values: 0 dBm is 1 milliwatt, 3 dBm is approximately 2 milliwatts, etc. How do I convert it to watts? Convert the decibel value to a scale factor and ...


10

Yes, crystal radios convert radio signals to audio without any additional power. But it is true that there is not much energy in a radio signal at any significant distance from the station, so a few tricks are involved to produce audio from that weak signal without any additional electricity: The earphones are special models that are high impedance and ...


10

A cross-meter is capable of showing you three measurements simultaneously: Output Power Reflected Power SWR From this image by Axel Schwenke on Wikipedia, you can see that the needle on the left indicates forward power, and the needle on the right indicates reflected power. The observed intersection of the two needles can be used to indicate the SWR of the ...


10

Electromagnetic hypersensitivity does not exist. There is no confusion. It has been rigorously refuted by science. One watt is orders of magnitude below safe exposure limits, and indeed probably less than exposure you are likely to get from cell phones, commercial broadcast stations, WiFi, and unintentional radiation from all kinds of electronics.


9

It depends on the frequency range the termination is rated for, and the power handling required. High power and high frequency is very difficult. At HF, any old non-inductive 50 Ω resistor will do. For higher power, we'd put many resistors in series and parallel, perhaps on a heat sink or in a can of oil. At VHF and UHF I've made very good terminations ...


9

The cheapest antenna you can set up is a speaker wire dipole. A spool of speaker wire long enough to split the conductors and make a center fed half wave dipole ought to cost around ten dollars US (or less). You can get useful radiation with supports made from cheap stud lumber from the home improvement store (8-10 dollars per support to get 5 meters off ...


8

You are making an unfair comparison. HTs and amateur repeaters use the same technology now as they did forever ago. If you want to compare HT performance with cell phones, compare it with one of these: In that light, I think HTs fare favorably. Modern HTs have grown more modern batteries (NiCd -> Ni-MH -> Li-ion), but the RF bits have seen about as much ...


8

Coverage maps are a thing that is notoriously difficult to do right. There are some very complex programs (Radio Mobile is the one I know the most about) which can generate coverage maps if you're prepared to wade through the technical details and the quirks of the software. Unfortunately it's not as easy as drawing a circle of a certain size around each ...


8

Trying to work it out I did: 20W (in) = 10log10(20W/1W) = 13dB(W) 15W (out) = 10log10(15W/1W) = 11.76dB(W) so, component power loss = 13dB(W) – 11.76dB(W) = 1.24dB(W) Your error is merely in the units, not in the calculation. Taking the difference of two dBW (or any two absolute dB values using the same reference level) gets you dB. If you want to think ...


7

The short answer: \begin{equation} \frac{V_{p-p}}{V_{rms}} = 2\sqrt{2} \end{equation} The long answer, or how to derive the above: As noted on the Wikipedia page for root mean square, the RMS of a sine wave is equal to its amplitude divided by the square root of two. (You can also derive this by doing the integral over a sine wave yourself.) \begin{...


7

It's about transmission duty cycles. For example, FM has a very high duty cycle during transmission: the transmitter's output power is constantly at 100% regardless of the amount of modulation. AM varies between 50% (carrier only) and 100% (full modulation). SSB varies with modulation between 0% and 100%. CW is like FM, 100% power output during transmission,...


7

Decibels are all "ratios" at their core. A unitless dB is a simply a ratio of one number to another, perhaps input power relative to output power. We can also use decibels for absolute values, by fixing the denominator to a standard reference — e.g. one milliwatt in dBm. But the most convenient thing about decibels is that, although they are ratios, because ...


6

A properly calibrated cross-needle power meter such as e.g. the MFJ-842 actually tells you something more than just the forward and reflected power, which as you point out can just as easily be indicated by two separate instruments. The intersection of the needles gives you a pretty good indication of the actual standing wave ratio or SWR because the SWR is ...


6

I think you pretty much summarized limiting factors in the general case. I'd add that there can be dielectric losses or breakdown at the ends, as well as the feedpoint. Common antenna designs (quarter-wave verticals, center-fed half-wave dipoles) are fed at a low-impedance node, and the ends are high-impedance nodes, so I'd expect dielectric breakdown (...


6

If you search for "automatic power off car ham" you'll find a number of solutions which don't require additional wiring. When the engine is running the voltage supply is higher than when the engine is off, so these work by sensing when the voltage is high enough, and turning the radio on.


6

While many transceivers and scanners can be powered by a cigarette lighter adapter, you typically want to run at most one transceiver in this way, and should make absolutely certain that you know where that lighter is getting powered from. Most car fuseboxes are relatively easy to access, and most owners manuals will tell you what fuse is associated with ...


6

This is not commonplace. Most operators in the UK get along fine with the 400W limit. Given the path losses inherent in Earth-Moon-Earth - hundreds of decibels - the antenna is a much more important factor than is the power. You need every extra bit of push you can get, but if you're not making it at 400W, 1500W isn't likely to be much better. Remember that ...


6

There are a lot of ways to approach this problem, but here's one: we can calculate the power density of that field, and determine the area from which the antenna captures power, and multiply them together. Calculating the power density If we know the electric field to be 1 mV/m, and the transmitting antenna is distant, then the magnetic field must be ...


6

I'd speculate a large part of the justification is that amateur stations, unlike commercial broadcast stations, are not periodically certified to meet spurious emission regulations. Or any regulations at all. While the station operator is responsible for ensuring the proper operation of his or her station, realistically amateurs will not always have the ...


6

Yes. Just like any other electronic device producing a signal, the transmitter is “really” applying a voltage to the output, which causes a current, and so on. But we talk about power more often because power is a much more useful figure to work with for RF engineering above the level of designing circuits; voltage and current can be traded off (while ...


6

I convert the 27dBm and 3dBm -> 10^2.7-10^0.3. But how can we simply subtract the two dBm If you convert to exponential form then you must simultaneously replace subtraction with division (or addition with multiplication), so you have $10^{2.7} / 10^{0.3}$ instead of $10^{2.7} - 10^{0.3}$. Then you will see that you get the same result: $$2.7 - 0.3 = 2.4$$ ...


6

Think about it this way. 27 dBm means 27dB above a milliwatt. Take 6dB away. Now you have something that's 21 dB above a milliwatt. Or, 21 dBm.


6

If the frequency counter is measuring -5.3 dBm, then before 20 dB of attenuation the power was 20 dB more than that, so 14.7 dBm. "dBm" means decibels relative to 1 milliwatt. 14.7 decibels can be converted to a ratio like so: $$ 10^{14.7/10} = 29.5 $$ So 14.7 dBm is 29.5 milliwatts.


6

That's an expected phenomenon: Real-world physical systems tend to be frequency-selective (i.e. not constant over frequency), and "at large scale" low-pass systems. This applies to amplifiers, mixers, oscillators, and even transmission lines and connectors. So that's normal. Ettus even publishes exactly such measurements at https://files.ettus.com/...


6

Is it possible to do without the power amplifier at TX ... by using a high gain antenna for RX? It is. You need another 27 dB (37-10) of antenna gain in addition to whatever you included in your existing link budget. You can split that gain between the RX and TX antennas to avoid needing a very high gain antenna at one end. High gain antennas are also ...


5

Some radios, such as the Yaesu FT-857D, have a feature in the menu that allows you to set the unit to automatically power off after a user-chosen period of time. Search the documentation of your radio for such an option.


5

Cheap mag mounts, like many physically short antennas, have a coil in them to make up the correct electrical length. I am sure it's made with the finest materials available. But it's probably not. Even if it was, inexpensive means smaller gauge wire, cheaper connectors, etc. And so driving it at higher than it's rated capacity is going cause it to heat ...


5

Overview Title 47 Part 15 defines regulations which cover any device that Radiates RF, whether intentionally, unintentionally, or incidentally Doesn't require an individual license for operation While a device might not require an individual license to be operated, it may still require FCC testing. This applies most strongly to devices made to be sold to ...


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