One of the sample questions for the British foundation level test is:

An amateur has the choice of VHF or UHF for a particular contact of some 25km. Which statement below best describes his choice?

and the correct answer is:

The VHF option is most likely to give a better signal.

There was an equivalent answer with UHF instead of VHF and two almost non-nonsensical ones.

Why is VHF better than UHF in this situation?

  • $\begingroup$ @PhilFrostW8II and others very nicely explained this here some time ago, in several questions about path loss, aperture, antenna gain, and/or capture area. I couldn't find the exact one just now $\endgroup$ Oct 4, 2017 at 19:14
  • $\begingroup$ @MikeWaters You're probably thinking of this question, but that is specifically about interpreting a particular formula and isn't applicable to (as would be the reasonable here here) the case where you're using the same type of antenna at different design frequencies. $\endgroup$
    – Kevin Reid AG6YO
    Oct 4, 2017 at 19:17
  • $\begingroup$ Arguably related, not a duplicate because what it's asking is different: ham.stackexchange.com/questions/793/… $\endgroup$
    – Kevin Reid AG6YO
    Oct 4, 2017 at 19:18
  • $\begingroup$ @KevinReidAG6YO Thanks, but I thought there was a better one. $\endgroup$ Oct 4, 2017 at 19:20

3 Answers 3


This is an ill-posed question, since "best" could mean so many things. If VHF is so plainly best, why does anyone bother with UHF at all?

If you mean what option has a lower path loss, then sure VHF is the better option. But then HF would be even better. And why not go with ELF? As the frequency decreases, so do free space path losses.

Well, an ELF antenna would be many kilometers long. While ELF would certainly be "best" in terms of free space path loss, when considering the entire proposition including constructing such an antenna, ELF isn't "best" by what most people would assume as the criteria.

The difference between UHF and VHF is of course less extreme, but you still have to wonder, what are the optimization criteria? While VHF has a lower free space path loss, it also requires a physically larger antenna to achieve a comparable gain as UHF. So if "best" means "minimum physical size to realize a reliable link", then there's not much difference.

Or perhaps the use case is an interference limited point-to-point link. In this case, for antennas of equal effective aperture, the UHF antenna will have higher directivity, while likely being about the same physical size of a VHF antenna of equal effective aperture. So in this scenario UHF is superior, since the necessary directionality can be achieved by a physically smaller antenna on UHF.

Maybe you desire some degree of privacy. Again, the higher directivity at higher frequencies given a limited physical size makes higher frequencies better.

Or perhaps "best" means lowest equipment cost. Technology is always advancing, but it's generally true that electronics to operate at lower frequencies are older and cheaper, so VHF has an advantage here. In modern times the difference in cost between 144 MHz and 440 MHz isn't much, but if we are pushing the 3 GHz upper limit of "UHF", the opportunities to find cheap, used gear decrease. Unless you can use consumer commodity 2.4 GHz equipment, in which case economies of scale make it the cheaper option.

Or perhaps "best" means there's an available frequency to use. UHF allocations tend to be bigger and newer, and so have more unallocated channels.

Does "best" mean lowest noise floor? The natural noise floor generally decreases at higher frequencies, but man-made noise may be the bigger issue. Depending on what man-made sources you have to contend with, this could go either way. For example if UHF means specifically the 13 cm band, you may need to contend with the 2.4 GHz ISM band, including microwave ovens, cordless phones, and consumer Wi-Fi radios.

Or perhaps you'll consider that for frequencies too high to support ionospheric propagation, the radio horizon imposed by the height of the antennas can be more a limiting factor than raw power or free space path loss. In this case perhaps you would favor UHF for its smaller Fresnel zone, if your link is at the limits of the radio horizon.

Maybe "best" means the signal can penetrate buildings. In this case VHF is the winner, since lower frequencies generally penetrate better.

Or perhaps you need to communicate beyond the radio horizon, or you don't have a direct line of sight. In this case UHF may be better since decreased building penetration means more effective reflection, thus allowing a building to be used as a passive reflector, for example.

Or perhaps your concern is what equipment the other operator has? Or what local repeaters exist? Such simple practical considerations often outweigh more theoretical ones.

I could go on, but the point should be clear: while the question clearly expects an answer framed by free space path loss, this is only but one consideration, and a minor one at that. In practice on VHF and higher, radio horizon and interference are the limiting factors. For digital modulations especially, multipath distortion limits range. And while not much of a problem for hams, the monetary cost of obtaining an allocation is probably the primary factor in selecting a frequency. It's a shame that an amateur radio exam reduces what's actually a multi-faceted problem to rote memorization or just free space path loss, but there you have it.

  • $\begingroup$ I guess "Best" is indeed a subjective term when viewed using a variety of criteria. Excellent answer by the way,,,, +1 $\endgroup$
    – Old_Fossil
    Oct 5, 2017 at 7:27
  • 3
    $\begingroup$ A colleague of mine uses to say: "Physics doesn't discriminate against higher frequencies; what you lose in path loss is identical to what you win in antenna gain for antennas of the same síze". Questions like the one OP took from the British exams make me angry; they actively lie about the fact that things are actually multi-faceted and can technically be very well explained and understood with enough nuance by beginners and encourage people to learn nonsense just for the test. Having such questions in official tests hence makes a community dumber, not better educated. $\endgroup$ Oct 5, 2017 at 11:55
  • $\begingroup$ @MarcusMüller -- Ditto! $\endgroup$
    – K7PEH
    Nov 19, 2017 at 21:20

The answer is correct - VHF will generally be more effective.

For like antennas of a specified gain (typically dBi), the energy transfer will be higher as the operating frequency is decreased.

This may at first seem to be an odd condition since if the gains of the antennas are the same and all other things are equal, shouldn't the received energy be the same regardless of frequency? The answer lies in the effective size of the antenna.

For example, a 1/4 wave vertical antenna on VHF has a length of about 50 cm. A 1/4 wave wave vertical antenna on UHF has a length of about 17 cm. Both antennas have the same gain. But placed the same distance from their respective transmitters, the longer length of the VHF antenna will intercept and collect more energy. Said another way, the VHF antenna is exposed to more radiant flux. Since the VHF antenna is nearly 3 times longer, it is exposed to nearly 3 times the radiant flux. As a result, the VHF antenna develops more power at the receiver terminals than the UHF antenna. In fact, the VHF signal will be more than 9.5 dB stronger than the UHF signal (~$20\log(3)$).

For a deeper understanding of the impact of the change in frequency, study the Friis equation below, taking note of the frequency term, or use one of the many on-line calculators.

$$ \text{Path Loss (dB)} = 20\log(d) + 20\log(f) +32.44 - G_{\text{TX}} - G_{\text{RX}} $$


$d$ = distance in km
$f$ = frequency in MHz
$G_{\text{TX}}$ = transmitter antenna gain in dBi
$G_{\text{RX}}$ = receiver antenna gain in dBi

  • $\begingroup$ @KevinReidAG6YO Thanks, Kevin for the formatting edit. I was just going in to fix that but I see you are faster than me at MathJax. $\endgroup$
    – Glenn W9IQ
    Oct 4, 2017 at 20:25

The VHF option is best because path loss generally increases with frequency in real outdoor environments.

An example where UHF might be the better option would be for an indoor link of tens of meters. UHF is more prone to multipath scattering than VHF, which actually would provide more signal paths for the indoor UHF link over a VHF link. The positive effects of multipath scattering (usually seen as a bad thing) over a short range would outweigh any path loss advantage at VHF.


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