I am looking for ideas to improve my Impedance measurements I perform on my VLF antenna system.

Due to circumstances my VLF experiments are usually "on location / in a field" so I do not have the luxury of a fully stacked workbench.

The setup I have is: - a function generator - 4000 Hz output - an audio amplifier - feedline - Antenna

I consider the feedline part of the antenna system, and I use the following method of determining the Impedance of the antenna system:

  • Measure the open output voltage of the Amplifier = Vopen
  • Measure the output voltage with a known load (Rload=1000) = Vload
  • Calculate the output impedance of the amplifier Rout = Rload * ((Vopen/Vload)-1)
  • Measure the output voltage with the antenna system = Vant
  • Calculate the antenna system impedance Rant = Rout / ((Vopen - Vant)-1)

I would repeat this process with multiple values of Rload to ensure measurements are accurat; usually I use the following values: 1000 Ohm and 2400 Ohm.

This way I can determine/tune the antenna system to come as close to 8 ohm impedance which the amplifier wants to see.

My questions are:

1) is this method correct ?

2) are there better methods given the limitation of being "on location" ?

  • 1
    $\begingroup$ If what you really care about is an antenna system that works without knowing the specific impedance, you can just hook a receiver up to it then twiddle the knobs on an antenna tuner until you get the strongest received signal. $\endgroup$ May 12, 2016 at 17:45
  • $\begingroup$ @PhilFrost , I did indeed tried this. I have two manual tuners here in the shack, but the variable capacitors are in the range of pF, while at 4kHz frequencies I like to have uF to have any noticable effect. Thanks for the response though! $\endgroup$ May 13, 2016 at 6:15
  • $\begingroup$ Im having almost the same esue my 2 Channel audio amp. Is capable of delivering 2000 wat rms per channel. And By connecting my 1500w 50 ohme impedence vlf antena, it hardly pulles 1 amp with out a resistor. But doing the same experiment with a resistor the amps increases to 40 amps with out helping my vlf antenna much to have more load.. The resistor takes almost all the load and the antinna still pulling 1 amp.. I wish to find a way to operate my antenna at its limite 1500 Watts..??? $\endgroup$
    – Nasser
    Feb 11, 2022 at 5:28
  • $\begingroup$ Building a experimental tuner with circuits tune for your custom resonance ranges for experimental purposes is well within most budgets! $\endgroup$
    – user21417
    Feb 11, 2022 at 13:31

2 Answers 2


At 4 kHz you could use your laptop as a rudimentary two-channel oscilloscope.

First find out if it has a useful two-channel input sound card, and find a way of recording a stereo 16-bit WAV and processing it. Octave or Python would work, or you could write your own.

Then build a circuit like this, adjusting parameters to suit:


simulate this circuit – Schematic created using CircuitLab

I've chosen to float the laptop and measure current in the live wire, as the laptop is the most likely part of the circuit to be battery powered. Keep the laptop away from the ground and don't connect anything else to it.

Now you may see a graph of Voltage (R) and Current (L) like this:
In Phase
Meaning your load is purely resistive, or like this:
Meaning your load is purely capacitive, or like this:
ComplexLoad Which will give both the magnitude and phase relationship of the voltage and current, allowing you to measure your antenna impedance.

You should probably calibrate the whole thing - try it out with a 1k resistor instead of the antenna, and check voltage/current readings, then try a modest capacitor and check that you get the right impedance.

I've used this method with a high speed 'scope, to measure an unknown impedance at 500 MHz. Results were within 10% of the network analyser figures.

PS. For an 8-ohm source and antenna, you'll need a much smaller current sense resistor, perhaps 0.1 ohms. I was still thinking of higher impedances.

  • $\begingroup$ THANKS ! this is something which can be done easily on location without purchasing equipment... thanks for the tip for Octave, never used it, so I will have to "play" with that ! $\endgroup$ May 13, 2016 at 6:21

Your method only crudely measures the magnitude of the feedline impedance, without taking into account the fact that it is probably a complex value, with a phase shift between voltage and current.

Also, the output impedance of most modern audio power amplifiers is very low — usually way less than an ohm. I'm surprised that you get any useful answers by testing it with 1000Ω and 2400Ω load resistors. The goal here is not to match the output impedance of the amplifier, but rather to maximize the power delivered to the antenna without exceeding the amplifier's capability to deliver current (i.e., without driving it into clipping). When an amplifier is "rated for" 4Ω or 8Ω or whatever, it simply means that its voltage output and current output capabilities both max out at about the same time with loads in that range.

It would be far more interesting to take a portable 2-channel oscilloscope (e.g., a USB device plugged into your laptop) and a current probe along on your field trip so that you can simultaneously measure both the voltage and current at the feedline input — and also do an instantaneous power calculation, assuming that your scope has the appropriate math features.

  • $\begingroup$ Thanks for the answer, the output impedance of the audio amp I am using measures around 150 Ohm at 4000 Hz... I don't have a 2-channel oscilloscope which is "portable"... on my wish list at the moment $\endgroup$ May 12, 2016 at 15:57
  • $\begingroup$ In that case, perhaps you should describe in greater detail (edit your question) what it is you're trying to achieve in this stage of your experimentation. $\endgroup$ May 12, 2016 at 16:45
  • $\begingroup$ I noticed I am getting the answers I am aiming for, so I guess the question does not need to be edited. Thanks for the tip, I certainly will introduce some sort of current measurements in my experiments. $\endgroup$ May 13, 2016 at 6:16

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .