I have the following example taken from the "ARRL General Class Manual", 7th Ed, 4-4.
Here's a practical application. Suppose you are using an antenna feed line that has a signal loss of 1dB. You can calculate the amount of transmitter power that's actually reaching our antenna and how much is lost in the feed line.
$$\text{Percentage Power} = 100\% \times \log^{-1}\left({-1\over10}\right) = 100\% \times \log^{-1}(-0.1) = 79.4\%$$
I think I'm missing something extremely trivial. In my calculator, I get
$$ 10^{-.1} = 9.9 $$
I don't have inverse log on my calculator but $ 10^{x} $ should be the same, no?
I think I'm missing the point with multiplying by 100% — that makes no sense to me. Either way I'm not sure how doing something to 9.9 with 100% gets me 79.4%.