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I've read the APRS spec, but can't for the life of me figure out where Direwolf is getting certain info. Looking at the output below:

Digipeater ZS6PJH-2 audio level = 55(23/12)   [NONE]   _____:|__
[0.6 11:24:46] ZS6JV-2>APDW17,ZS0ERB-5,ZS6PJH-2*,WIDE2-1:;ZS6JV-2  *111111z2638.28S\02756.20E&Internet Gateway
Object, "ZS6JV-2", I=Igte IGate R=RX T=1hopTX 2=2hopTX, DireWolf, WB2OSZ
S 26 38.2800, E 027 56.2000
Internet Gateway
mheard_save_rf: ZS6JV-2 2 - update time, was 2 hops 5 seconds ago.
callsign  cnt chan hops    RF      IS    lat     long  msp
ZS6JV-2     9   0   2     0:00    0:04  -26.64   27.94  0
ZS4OIL-1   15   0   2     0:00     -    -26.69   27.81  0
ZR6N-1      9   0   1     0:01     -    -26.10   28.02  0
ZS6MJS-10   7   0   0     0:03     -    -25.79   28.31  0
ZS0ERB-5    1   0   1     0:10     -    -26.39   28.00  0
ZS6BVJ-9   30   0   0     2:30     -    -25.78   28.32  0
ZS6JCO-1    2   0   4     2:37     -    -26.77   27.84  0
[0H 11:24:46] ZS6JV-2>APDW17,ZS0ERB-5,ZS6PJH-2,ZS6MJS-10*:;ZS6JV-2  *111111z2638.28S\02756.20E&Internet Gateway

I can't see which part of the APRS packet:

ZS6JV-2>APDW17,ZS0ERB-5,ZS6PJH-2*,WIDE2-1:;ZS6JV-2  *111111z2638.28S\02756.20E&Internet Gateway

Decodes to the below:

I=Igte IGate R=RX T=1hopTX 2=2hopTX
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1 Answer 1

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The \ and & after the latitude and the longitude respectively make up the symbol: \&. The descriptions that direwolf displays for symbols come from the data files symbolsX.txt and symbols-new.txt which are sourced from aprs.org.

The description for \& in symbolsX.txt is I=Igte R=RX T=1hopTX 2=2hopTX, which is where that's coming from, but it turns out to be quite a confusing message. It's in that file to convey the fact that I& should be used to mean "generic igate", R& to mean "RX-only igate", T& to mean "TX igate (with a 1-hop path)", and 2& to mean "TX igate (with a 2-hop path)"... and that \& is no longer recommended for use as a symbol. Direwolf is kind of displaying it out of context here. Usually the descriptions are more immediately useful.

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  • $\begingroup$ Perfect, thanks a bunch. $\endgroup$
    – s3c
    Dec 6, 2021 at 4:03

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