I guess my question is as follows: if I find FSPL (there will be no buildings or anything blocking/diffracting), can I figure out how far the signal can be transmitted if the receiver gain, loss and sensitivity as well as the transmission power and gain/loss is known.
All I really know is the frequency of the RF (around 730 MHz), the TX Power (6dBm), the antenna gain (-21 dB), RX Sensitivity.
Since I cannot really find FSPL (free-space path loss) because you need the distance transmitted for that, I am kind of at a loss (no pun intended) as to how to find the possible transmitted distance.
So, is there a way to figure out (based on a receiver's loss/gain and sensitivity) what minimum value (I guess dBm) would be needed for a signal to be decipherable? (I have heard that 3 dB or dBm or what ever measures this is a good assumption...)
Also, I know
RX power = TX power + gains - losses and FSPL is a loss (which has distance built into the formula). Since
**FSPL** (dB) = 20log(**distance**) + 20log(**frequency**) + 32.45 (for kilometers) that means that
distance = 10^(**FSPL** (db) - 20log(**frequency**) - 32.45)/20. The problem is that there is no way to find the FSPL value in the second equation because in order to find that, you need the distance which is what we are trying to find in the first place!! So, you would be able to solve the initial equation (with RX power = TX power + gains - losses) equal to distance, but you would have no way of finding th FSPL value.
Thanks for your help, Phil! It turns out we cannot even estimate the distance because the TX power outputted can not truly be found.