 The transmission line is without loss of length λ / 4, the load $$Z_L$$ is a short circuit and $$Z_G = Z_0$$.

At $$t = 0$$, an incident wave of voltage $$V_1$$ and current $$I_1$$ such that $$V_1 = Z_0 * I_1$$ travel to the load, before $$V_1$$ reaches plane B the source $$V_G$$ delivers a power $$P_G = V_G^2 / (Z_G + Z_0)$$, then the waves $$V_1$$, $$I_1$$ reach the plane B and are fully reflected, generating reflected waves $$V_2$$, $$I_2$$ such that $$V_2 = Z_0 * I_2$$ that travel towards the source $$V_G$$, both form standing waves of total voltage $$V = V_1 + V_2$$ and total current $$I = I_1 + I_2$$ such that in plane A, $$V / I = Z_{in} = ∞$$ then the source sees an open circuit at A and cannot deliver any more energy.

If the above is correct, my questions are:

1. once the $$V_2$$, $$I_2$$ waves reached the source, what happens to them?
2. If the answer is that they dissipate in $$Z_G$$, where does that energy come from? since the source sees an open circuit ($$Z_{in} = ∞$$) and for this to happen I need $$V_1$$, $$I_1$$ and $$V_2$$, $$I_2$$ at all times.