Looking at the diplexer schematic from this nice question,

Diplexer schematic

I realized this can completely be done in PCB-formed elements (minus the connectors). (As a kind of counter-action to the original question's intent to get leaded capacitors, I'm not only trying to eliminate the leads, but also the discrete components.)

  • the 50Ω aren't actually resistors, they are the wave impedance of the cable / device you attach there
  • a 20mm × 20mm rectangular plate capacitor formed by patches on the top and bottom layer of a 0.8mm thick piece of FR-4 ($\varepsilon=4.7\varepsilon_0$) is about 20 pF
  • There's PCB coil designs that provice up to µH in inductance.

Now, assuming I don't plan to work with as high power as the original question, but still substantial power (5W) in a relevant range of 20 MHz – 500 MHz:


  1. a planar coil antenna
    planar coil, field normal to substrate
  2. a coil formed through alternating between layers (so that the main magnetic flux is inside the substrate) PCB in substrate coil

be most effective?

  • I'm told (but I don't have access to the software to simulate that) that planars have low Q. I have no such information on the other choice.
  • Which design has lower self-capacitance?
  • $\begingroup$ Marcus, glad that something good comes from my question. Would be very interested to see how it turns out and how you proceed. Any chance you'd care to document it somewhere? $\endgroup$ – Dieter Vansteenwegen ON4DD Jul 11 at 17:09
  • $\begingroup$ Since all coils would be in the same plane, would that not lead (no pun intended) to too much coupling? $\endgroup$ – Dieter Vansteenwegen ON4DD Jul 11 at 17:10

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