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I read in some text books that

  1. E-plane is formed by taking constant azimuth angle and scanning elevation angle from -90:90.
  2. H-plane is formed by taking a plane perpendicular to E-plane.

What is the meaning of taking a plane perpendicular to E-plane?? Is it to take constant elevation angle and scan azimuth angle from -90:90?

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    $\begingroup$ Please, share with us the text book where you found this information. $\endgroup$
    – Brian K1LI
    Dec 3, 2019 at 12:54
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    $\begingroup$ Harry L. Van Trees - Optimum Array Processing (Detection, Estimation, and Modulation Theory, Part IV) (2002).PageNo:242. $\endgroup$
    – kartheek
    Dec 4, 2019 at 11:42
  • $\begingroup$ Hello, and welcome to this site! That seems to be a well-respected, scholarly book. I can't seem to find the book where he says that, but could it be that he says something along the lines of what Marcus said? $\endgroup$ Dec 4, 2019 at 19:43
  • $\begingroup$ I searched other editions of this book (since the 2002 edition is not available to view on books.google.com, and I couldn't find E-plane. Could you please edit your question and post a photo of that page? Thanks! $\endgroup$ Dec 4, 2019 at 20:05
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    $\begingroup$ Sorry, this page seems to have nothing to do with E- or H-Planes. Could you explain, @kartheek? $\endgroup$ Dec 5, 2019 at 19:25

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Those definition are false.

The E-plane is defined as the plane in which the E-field varies over time. The H-plane is the plane in which the H-field varies over time.

There's nothing more to it.

Logically, the definition of planes only makes sense for linearly polarized antennas.

In isotropic (meaning: behaving the same from every angle) media (e.g., air), the H-plane is always perpendicular to the E-plane. Perpendicular is when two planes are at a right angle to each other.

Whether the E-plane is in azimuth or elevation or somewhere in between depends on the direction of polarization of the antenna.

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  • $\begingroup$ @hobbs-KC2G ooops, yes. $\endgroup$ Dec 4, 2019 at 8:25
  • $\begingroup$ He has included the page in question. Any thoughts? $\endgroup$ Dec 5, 2019 at 16:44
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    $\begingroup$ @MikeWaters not really – that page nowhere mentions an E- or H-Plane. $\endgroup$ Dec 5, 2019 at 19:26

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