I tried to understand the physics of Fuchs antenna and there is one thing that I don't quite understand. This is probably a very silly question, but I spent a lot of time looking for an answer (books, online) and didn't manage to find it.
Modern Fuchs antenna looks like this:
The L1,L2 is a transformer, typically 64:1 or 49:1. It is required because the end fed half wave wire has an impedance about 2500..3200 Ohm, assuming a counterpoise wire is about 0.05 lambda. OK, this is clear.
Also the L2,Cv circuit has to resonate on the frequency of interest (e.g. 7.1 Mhz for 40m band). This is the part I don't quite understand. Why using only a transformer is not enough to convert 2500..3200 Ohm to 50 Ohm of the feed line and feed the antenna as a regular dipole? Why we also need a capacitor to form a resonant circuit? Or, in other words, what happens if we remove Cv?
I'm not an expert in antennas or physics. I would appreciate very much if you could explain it like I'm 10 years old.