# How might one realize a first order, two dimensional RF field antenna for HF?

I just coined the term "field antenna". It is by analogy to the lightfield camera or the soundfield microphone. Essentially, it is an antenna that captures not only the strength of an RF field, but also the direction of it.

Of course, these antennas already exist in forms, such as phased arrays used for radar, or four-square antennas popular on the lower bands. However, I have a somewhat different use case in mind: I want it to work at HF, for receive only, and I don't want to implement the phasing with a fixed network (or maybe a few switched networks) as in the four-square antenna. Instead, I want to perform the phasing in software.

One possible application: listening to radio in stereo, with the sound heard corresponding to the direction from which the signal was received, a "wetware rotator" of sorts.

Now, the usual way to doing this processing is to decompose the signal into circular harmonics. These are like spherical harmonics, but in two dimensions (circles) instead of 3 (spheres). For the sake of simplicity I'm stopping at the first harmonic (first-order), so I will have, perhaps after some processing, three signals:

1. an omnidirectional signal (0-th order)
2. a figure-of-eight pattern aimed East-West
3. a similar figure-of-eight, but aimed North-South

Described mathematically, I'm looking for the responses in azimuth defined by:

$$\frac{1}{\sqrt{2\pi}}, \frac{\cos \theta}{\sqrt{\pi}}, \frac{\sin \theta}{\sqrt{\pi}}$$

or described graphically: Now here's the question: how might one realize such an antenna? Remember the antennas need not actually have these responses: they might have other responses from which these responses can be calculated.

• I wonder if it would be easier to use three sdr receivers sharing the same mixing clock and ADC clock, resulting in three I/Q pairs. Requires more hardware, of course, but easier for me to wrap my head around. Looks like the first answer is suitable for finding the direction of a single signal, but with separate receivers sharing a clock it should be possible to determine the direction of all signals received. Could do some pretty amazing noise reduction with that info, I'd think, too. Dec 22, 2013 at 6:58
• @AdamDavisKD8OAS that's the idea, actually. The question is just to what antennas these SDRs are connected. I'm pretty sure it's an array of verticals somehow, but I'm not sure exactly how, and how many. Dec 22, 2013 at 12:29
• I'm not sure if this matches any/all of your criteria specifics, but I recently came across a fun presentation on a Wideband Direction Finder with Colour Encoded Spectrogram Dispaly that should be at least somewhat relevant/interesting to this question. Jan 6, 2016 at 21:21

OK, this is an interesting one.

At first blush you could achieve this with two tuned magnetic loops at right angles to each other (visualize an egg-beater) and a 1/2 wave vertical for the omnidirectional part.

Of course, someone has thought of this crossed loop arrangement before, in 1907 Bellini and Tosi invented the Bellini-Tosi Goniometer: A coil is rotated inside an electrical field fed from the N-S and E-W antenna signal components such finding the angle of maximum signal. The antenna can be either be a circular array of 1/4 wave verticals or a Crossed-Loop Antenna: Systems based on this principal were the basis of the first radio navigation systems for aircraft until replaced by radar following WWII.

Back to the original question though, I think the loops would have to be tuned fairly precisely and high-Q loops are rather narrow in bandwidth so you'll have to pick your operating frequencies with care. But I don't see any obvious reason why it couldn't be done.

• Well, the crossed loops thing is viable, but it's missing the omni part, so has a 180 degree direction ambiguity. Adding a vertical I don't think would work well, because the loops and the vertical have a different elevation pattern. There is an "adcock antenna" which has the azimuthal pattern of a loop and the vertical pattern of a vertical, but two adcocks and a vertical is five antennas, and maybe a bit impractical. Intuition tells me there's a simpler way, if one allows for some DSP. Dec 21, 2013 at 20:42
• Also, why would the loops need to be tuned? Dec 21, 2013 at 20:47
• There shouldn't be ambiguity with the two loops together. But, this is clearly in the realm of speculation until on is built and messed with. The loops would have to be matched, I would think, to ensure you are working with the same pattern, gain, etc. Dec 21, 2013 at 21:03
• I'm almost certain the two loops have a 180 degree direction ambiguity. Combining them gives you the same pattern as a loop, but rotated by an arbitrary amount. If the signal is in one of the nulls, how do you know which one? If it's in one of the lobes, one is positive and one is negative, but since you don't know the phase of the signal, you still don't know the direction. The omni in the middle resolves this: now you do know the phase of the signal. Dec 22, 2013 at 12:54

Three verticals (or three vertical dipoles) arranged in a triangle, spaced less than $\frac{1}{2}\lambda$ apart should do it.

Any pair of these antennas could be considered as an Adcock antenna. Each has the desired figure-of-eight response, and with the three antennas, we have three of these, each aimed sixty degrees apart. Unlike a traditional Adcock antenna, we won't be combining the antennas electronically, but rather connecting each element to an SDR (each phase-synchronized) and the combining is done in software. This allows each antenna to be arbitrarily combined with any others, in perhaps multiple ways simultaneously.

We could describe the azimuthal responses of each of the three possible pairs as:

\begin{align} f_1(\theta) &= \cos \theta \\ f_2(\theta) &= \cos (\theta + \frac{\pi}{3}) \\ f_2(\theta) &= \cos (\theta + \frac{2 \pi}{3}) \\ \end{align}

These can be combined in some ratio to arrive at the desired patterns from the question. We can see that the ratios will be multiples of $\frac{\pi}{2}$ because:

$$\int_0^{2\pi} f_2(\theta) \cos (\theta)\,d\theta = \frac{\pi}{2}$$

So we can then reconstruct the first-order circular harmonics as:

\begin{align} h_{1a}(\theta) &= f_1(\theta) &+\frac{\pi}{2}f_2(\theta) &-\frac{\pi}{2}f_3(\theta) \\ h_{1b}(\theta) &= &-\frac{\pi}{2}f_2(\theta) &-\frac{\pi}{2}f_3(\theta) \end{align}

A graph might help: This shows the response of the three possible pairings. $f_1$ is red, $f_2$ is yellow, and $f_3$ is green. $h_{1a}$ is cyan, and $h_{1b}$ is blue. Only the positive lobes are shown to make the polarity of the signals easier to see.

The 0th order response, the omnidirectional one, is easy: it's simply the average of the three antennas. This is equivalent to a vertical antenna in the middle of the triangle array. This serves to sense the phase of the signal so we can know if it is in the positive or negative lobe of the 1st harmonics. Without it, there would be a 180 degree direction ambiguity in any measurements.