I hear all the time, "you need a balun between your balanced dipole and unbalanced coax to stop the common-mode current" when it seems the proper advice is "you need something to stop common-mode current (full stop)." Sure, attaching a balanced system (e.g. dipole) to an unbalanced system (e.g. coax) is a frequent source of common-mode current. But, this answer points out that even with a so called "balanced" antenna connected to a balanced feedline, the antenna often isn't really balanced, so some sort of common mode choke is a good idea no matter what.

So, if the same advice applies either way, why do we make such a big distinction between balanced and unbalanced? My assumption is that it's one of a couple things:

  • Misconception: A lot of people may not realize a common-mode choke is recommended anyway.
  • Old knowledge: This is sort of a special case of misconception. Maybe in the past, we didn't think of common-mode suppression as a generally recommended thing, and only later did it become common knowledge that this is a good thing even in balanced systems. Meanwhile, outdated information persists.
  • Other reasons to differentiate: Even though common-mode suppression is a good idea regardless of balanced vs. unbalanced, there may be other ways we do treat them differently, or other reasons to distinguish between them.

My suspicion is the first one is true to some degree, but that the third case is the main reason.

To further muddy the waters, I'm seeing the word "balanced" used in two seemingly different ways. One is in the sense above where, for example, we have a "balanced" dipole that's actually unbalanced because one side is close to a hunk of metal, causing it to present an unbalanced impedance at the feed point. The other way I've seen it used is to represent a system where the two conductors have equal and opposite voltages relative to ground, versus unbalanced where one of the conductors is grounded. Are these two uses of the word actually the same thing? If so, how?

  • $\begingroup$ we need to distinguish between them because they are different things. Full stop. The common mode choke thing is a separate issue! $\endgroup$ Apr 18, 2018 at 15:55
  • $\begingroup$ @MarcusMüller I just added an edit before seeing your comment but it seems like you're saying the answer to my edit is no, they are not the same thing. In which case, I'm wondering if the only reason the two always come up together is that connecting balanced and unbalanced systems is one of the more frequent sources of common-mode current. Which is misleading since there are other sources. $\endgroup$ Apr 18, 2018 at 16:07
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    $\begingroup$ Could you revise your question so it is not in three restatements with "Edit:"? We want things that are easy to read as a clearly stated question and matching answer, without people having to piece together multiple stages of reaching it. $\endgroup$
    – Kevin Reid AG6YO
    Apr 18, 2018 at 18:44
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    $\begingroup$ @KevinReidAG6YO Yes, I guess it has gotten unwieldy. I will revise it. $\endgroup$ Apr 18, 2018 at 20:19
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    $\begingroup$ Suggest reading the following for a understandable and thorough treatment of common mode chokes including easy to build (that is, can you wrap some wire around a toroid?) ones, with better performance and much cheaper than commercial units. K9YC is a professional engineer with decades of experience and a practical bent. audiosystemsgroup.com/publish.htm and look for: RFI, Ferrites, and Common Mode Chokes For Hams 73, George VE3YV/K8HI $\endgroup$ May 4, 2018 at 20:32

3 Answers 3


There are balanced feedlines (twin-lead), and balanced antennas (dipoles), and similar things all described as "balanced". In this sense, balance means the two halves of the thing have equal impedance relative to ground. Here, ground does not mean whatever is called ground on the schematic. Rather, it means "the environment".

Consider twin-lead for example. If the spacing between the conductors is small relative to wavelength, we can say they are effectively in the same space. And the wires have the same geometry. Since they're both the same (for frequencies low enough that this is a valid approximation), of course they are going to have the same impedance to the environment. Meaning, if an electromagnetic wave from a distant transmitter reaches the feedline, each half of the twin-lead will be affected equally.

This same property means if we drive the twin-lead with each half having an equal but opposite current, each individual half will have surrounding it an equal but opposite electromagnetic field. But these equal but opposite fields cancel, and thus the feedline does not radiate. It's this property that allows a feedline to move electromagnetic energy from one end to the other without much loss, or carry a signal from an antenna to a receiver without picking up noise from everything around the feedline.

For this reason, in discussion of feedlines, and the antennas and radios to which they are connected, you may encounter discussion of current balance. This just means equal but opposite currents, also known as differential mode current.

Coax is not a balanced feedline, which can be seen by considering how it would pick up an electromagnetic wave from a distant transmitter, for example. The wave will interact with the shield just like a fat wire, effectively an antenna. But the center conductor, being screened from the environment by the shield, isn't affected at all. The two parts of coax do not have equal impedance to ground, thus it is not balanced.

But coax does require balanced current. Only if the currents on the shield and center conductor are equal but opposite will the coax act as a feedline. Otherwise, it will radiate, or pick up noise.

It's for this reason the common-mode choke is so ubiquitous. Regardless of whether the feedline or antenna attached to it is balanced or unbalanced, differential mode current (AKA, balanced current) through it sees a low impedance, whereas common mode current (the remainder) sees a high impedance.

  • $\begingroup$ I feel like this almost answers my question, but just to clarify: You are saying that balanced current is always important, but the reason we make the distinction is that coax is happy to accept noise or radiate without any encouragement, but balanced line will not unless attached to an unbalanced antenna? (continued in next comment) $\endgroup$ Apr 18, 2018 at 21:53
  • $\begingroup$ This makes sense and now I see you were also saying this in your answer that I linked to in the question. The disconnect was not really understanding what "unbalanced" means in the context of feed lines. I was under the impression that any feedline only radiates or picks up noise when provoked by the antenna, and unbalanced meant it would be provoked by a balanced (or differently unbalanced) antenna. Or something like that. I'm not entirely sure. $\endgroup$ Apr 18, 2018 at 21:53
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    $\begingroup$ @Dominick Neither coax nor twin-lead will radiate or accept noise "without encouragement", but they accomplish that property through different means. In coax, noise currents stay on the outside of the shield, and by extension, the receiver enclosure. In twin-lead, noise cancels because the receiver measures only the difference between the leads, often by terminating it into a transformer winding. $\endgroup$ Apr 19, 2018 at 2:12

In the real world, most center-fed dipoles are balanced; and when we feed them with balanced line there is seldom a need for a balun where that feedline connects.

This post may help answer your question. Look at Phil Frost's first answer here: Using a balun with a resonant dipole

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    $\begingroup$ This is actually the same post I linked to in my question. That answer points out that connecting a balanced system directly to an unbalanced system creates common-mode current. Sure, but just because we use a balanced feedline with a balanced antenna design doesn't mean it will be perfectly balanced in practice. Many sources point out that a common-mode choke is still recommended. Maybe it's not so clear what I'm asking. I'll try and find a way to clarify my question. $\endgroup$ Apr 18, 2018 at 18:26
  • $\begingroup$ I've done it both ways, with little noticeable difference, except that my latest is 3 pairs of wires so the Balun along with a piece of acrylic, provide strain relief. But for a pocket, 75M antenna using magnet wire and wrapped on a fishline spool I wouldn't bother. (True story). $\endgroup$
    – SDsolar
    Apr 19, 2018 at 1:22

A current mode balun is typically used for suppressing common mode current on the transmission line. It can also be used for impedance transformation as seen in a 4:1 current balun design, for example. A so called choking balun is the equivalent of a current mode balun without impedance transformation.

Consider that most antennas are neither balanced nor unbalanced but rather somewhere in between. So a more constructive way of thinking about the ports of a current mode balun is simply that the "bal" port should connect to the antenna and the "un" port to the transmission line.

A coaxial cable transmission line and a balanced transmission line are both capable of carrying common mode currents. The physics are slightly different, but the result is the same - the feedline radiates and the feedline can couple undesired signals into the antenna system.

So when using a balanced line, a current mode balun is still warranted in order to suppress common mode current. You may include impedance transformation as part of the design to facilitate matching the balanced line to the antenna feedpoint impedance.

As an incidental comment, what amateur radio operators typically overlook is that the electrical length of the transmission line plays a significant role in the susceptibility of the transmission line to common mode currents. This is true for unbalanced (coax) and balanced transmission lines with or without a current balun.


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