Timeline for 1:4 Guanella unun current balun
Current License: CC BY-SA 4.0
3 events
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| Apr 28, 2021 at 19:11 | comment | added | Phil Frost - W8II | @ErikMcKee It seems like you are assuming there will be some shield current in the upper coax besides what's drawn in the image, but there is not. The shield current isn't 2i, it's just i. The center conductor is also i but in the opposite direction. There is no common-mode current. There can't be a significant common-mode current, because the common-mode impedance is very high. | |
| Apr 28, 2021 at 16:38 | comment | added | Erik McKee | Hi Phil, I have been thinking about the equivalency a lot. I agree differential current will not see the core in the lower picture. However, in the coax, you have current traveling down the inner conductor, and in the opposite direction on the inner wall of the shield conductor. The current that is added to the shield of the coax (from the signal pin of the lower coax) would travel on the outside braid of the shield conductor and not 'see' the inner conductor. The return current therefore should be 2i and there is not longer a differential current, its would be i going down, and 2i return? | |
| Apr 20, 2021 at 16:08 | history | answered | Phil Frost - W8II | CC BY-SA 4.0 |